Potential is different if there are charges in the sphere, which can be calculated using the image charges method. The electrons on the surface will experience a force. In other words, our point of interest is somewhere over here at an arbitrary location, or lets say some little r distance away from the center such that little r is smaller than big R inside the region and we choose our Gaussian surface, closed hypothetical surface, in the form of a sphere such that it passes through the point of interest. find the electric field at point A r<R and point B r>R using the superposition principle If that is the litteral rendering of the problem statement, you can't pretend the field of the shell is known, as in Davidllerenav said: saying that it would be the same as the field of a the spherical shell alone plus the field of a point charge -q at A or B Electric intensity is detected at all points outside the spherical shell as well as the center of the shell, implying that the charge is concentrated there. The whole charge is distributed along the surface of the spherical shell. The risk of online physics courses is that the, even MIT, material may not be properly reviewed for inaccuracies like these. When would I give a checkpoint to my D&D party that they can return to if they die? According to Gauss's law, as the charge inside is zero, the electric flux at any point inside the shell will be zero. From Gauss' law In fact, the electric field inside any closed hollow conductor is zero (assuming that the region enclosed by the conductor contains no charges). In a hollow cylinder, if a positive charge is placed in the cavity, the field is zero inside the cavil. The electric field inside a spherical shell of uniform surface charge density isOption 1)ZeroOption 2)Constant, less than zeroOption 3)Directly proportional to the distance from the centreOption 4)None of the above. Relevant equations are -- Coulomb's law for electric field and the volume of a sphere: E = 1 4 0 Q r 2 r ^, where Q = charge, r = distance. The electric field inside a spherical shell of uniform surface charge density is Q. How is this circle oriented? spherical shell has inner radius of J and an outer radius ofb Between these (a <r . Calculate the speed of the proton. Here I use direct integration of the expression for the electric potential to solve for the electric potential inside and outside of a uniformly charged sphe. The Higgs Field: The Force Behind The Standard Model, Why Has The Magnetic Field Changed Over Time. 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